QuestionAugust 27, 2025

Which expression is equivalent to sqrt [4]((24x^6y)/(128x^4)y^5) Assume xneq 0 and ygt 0 (sqrt [4](3))/(2x^2)y (x(sqrt [4](3)))/(4y^2) (sqrt [4](3))/(4xy^2) (sqrt [4](3x^2))/(2y)

Which expression is equivalent to sqrt [4]((24x^6y)/(128x^4)y^5) Assume xneq 0 and ygt 0 (sqrt [4](3))/(2x^2)y (x(sqrt [4](3)))/(4y^2) (sqrt [4](3))/(4xy^2) (sqrt [4](3x^2))/(2y)
Which expression is equivalent to sqrt [4]((24x^6y)/(128x^4)y^5) Assume xneq 0 and ygt 0
(sqrt [4](3))/(2x^2)y
(x(sqrt [4](3)))/(4y^2)
(sqrt [4](3))/(4xy^2)
(sqrt [4](3x^2))/(2y)

Solution
4.1(151 votes)

Answer

\frac{\sqrt[4]{3x^2}}{2y} Explanation 1. Simplify the fraction inside the root Simplify \frac{24x^6y}{128x^4y^5} to \frac{3x^2}{16y^4} by dividing both numerator and denominator by 8x^4y. 2. Apply the fourth root Apply the fourth root: \sqrt[4]{\frac{3x^2}{16y^4}} = \frac{\sqrt[4]{3x^2}}{\sqrt[4]{16y^4}}. 3. Simplify the denominator Simplify \sqrt[4]{16y^4} to 2y because \sqrt[4]{16} = 2 and \sqrt[4]{y^4} = y. 4. Combine results Combine to get \frac{\sqrt[4]{3x^2}}{2y}.

Explanation

1. Simplify the fraction inside the root<br /> Simplify $\frac{24x^6y}{128x^4y^5}$ to $\frac{3x^2}{16y^4}$ by dividing both numerator and denominator by $8x^4y$.<br /><br />2. Apply the fourth root<br /> Apply the fourth root: $\sqrt[4]{\frac{3x^2}{16y^4}} = \frac{\sqrt[4]{3x^2}}{\sqrt[4]{16y^4}}$.<br /><br />3. Simplify the denominator<br /> Simplify $\sqrt[4]{16y^4}$ to $2y$ because $\sqrt[4]{16} = 2$ and $\sqrt[4]{y^4} = y$.<br /><br />4. Combine results<br /> Combine to get $\frac{\sqrt[4]{3x^2}}{2y}$.
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